November 2, 2024
After some early morning text messages where I tried (and to be honest, failed miserably) to calculate his odds, I wrote a little program in C to do the calculation.
Then, because sometimes programming is fun, I decided to see what it would look like in Perl. I haven't written a ton of Perl, I usually lean towards PHP for this sort of thing, but I ported SWELL's resource-processor script to Perl a while back and enjoyed it, and having a simple task is good for learning.
The first pass I did used a builtin array shuffle module, which proved too slow, then I ended up simplifying it and got it significantly faster than the C version (which didn't reshuffle, but did end up with pointless memmove()s). Once I had it all working (using strict, e.g. you have to declare everything), I decided to see how small I could get it to be. Here's what I ended up with (you can pipe the table on their lottery entry page to it):
$nwin = 250; # I think the lottery picked about 250-something winners last year, the rest were golden tickets and such $nlot = 100000; # someone could quantify the margin of error based on this, with statistics you would oh look a bird for ($pid = 0; <>; ) { ($nt, $np) = split(/\s+/, s/,//r); ($nt > 0 and $np > 0 and not exists $wcnt{$nt}) or die "invalid input"; $wbin{$pid} = $nt; $wcnt{$nt} = 0; push(@tk, ($pid++) x $nt) while ($np-- > 0); } printf("%d tickets for %d entrants, running %d lotteries for %d winners:\n", $tkcnt = @tk, $pid, $nlot, $nwin); for ($x = 0; $x < $nlot; $x++) { %in = { }; $in{$id = $tk[rand($tkcnt)]}++ == 0 and exists $wbin{$id} and $wcnt{$wbin{$id}}++ while (%in < $nwin); } printf("%d tickets: %.2f%% win\n", $_, $wcnt{$_} * 100.0 / $nlot) foreach (sort { $a <=> $b } keys %wcnt);Here is the most recent input:
512 1 512 256 15 3,840 128 55 7,040 64 139 8,896 32 215 6,880 16 296 4,736 8 594 4,752 4 963 3,852 2 1,538 3,076 1 2,077 2,077and here is the most output with that table:
45661 tickets for 5893 entrants, running 100000 lotteries for 250 winners: 1 tickets: 0.66% win 2 tickets: 1.29% win 4 tickets: 2.56% win 8 tickets: 5.08% win 16 tickets: 9.99% win 32 tickets: 18.98% win 64 tickets: 34.12% win 128 tickets: 56.51% win 256 tickets: 80.91% win 512 tickets: 96.24% winSo, Steve's odds as of this afternoon are about 0.66%, but that will almost certainly go down (there's still a month left of the lottery; it only opened yesterday). Interestingly, one entrant there has been turned down 8 times before -- they currently have a 96% chance of getting in. And those who have been turnwed down 6 times before are slightly more likely than not to get in.
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